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Question: Find the area enclosed between x<sup>2</sup> + y<sup>2</sup> ≤ 9p<sup>2</sup> and Sin (x – y) ≥ 0...

Find the area enclosed between x2 + y2 ≤ 9p2 and

Sin (x – y) ≥ 0

A

9π34\frac { 9 \pi ^ { 3 } } { 4 }

B

9π32\frac { 9 \pi ^ { 3 } } { 2 }

C

3p3

D

p3

Answer

9π32\frac { 9 \pi ^ { 3 } } { 2 }

Explanation

Solution

It is clear by symmetry 2A = p(3p)2

A = 9π32\frac { 9 \pi ^ { 3 } } { 2 }