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Question: Find the amount which Ram will get on\[Rs{\text{ }}4096\] , if he gave it for \[18\] month at \(12\d...

Find the amount which Ram will get onRs 4096Rs{\text{ }}4096 , if he gave it for 1818 month at 1212%12\dfrac{1}{2}\% per annum, interest being compounded half-yearly.
A.Rs.4913Rs.4913
B.Rs.4425Rs.4425
C.Rs.4814Rs.4814
D.Rs.4124Rs.4124

Explanation

Solution

Before proceeding further we need the formula to calculate the amount when the interest is compounded half-yearly.
A=P(1+R100)t(1)A = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \ldots \left( 1 \right).
Where,
A=Amount P=Principal R=Rate t=time  A = {\text{Amount}} \\\ P = {\text{Principal}} \\\ R = {\text{Rate}} \\\ t = {\text{time}} \\\

Complete step by step solution
When we are calculating compound interest yearly there is no impact but in case of the half-yearly, there is impact on time as well as rate.
In this question we have,
A=? P=4096 R=1212=12×2+12=252 t=18 month  A = {\text{?}} \\\ P = {\text{4096}} \\\ R = 12\dfrac{1}{2} = \dfrac{{12 \times 2 + 1}}{2} = \dfrac{{25}}{2} \\\ t = {\text{18 month}} \\\
Now we need to calculate time in a year.
12month=1year 1month=112×year 18month=1812year  = 32year  12\,{\text{month}} = 1\,{\text{year}} \\\ 1\,{\text{month}} = \dfrac{1}{{12}} \times {\text{year}} \\\ 18\,{\text{month}} = \dfrac{{18}}{{12}}{\text{year}} \\\ {\text{ = }}\dfrac{3}{2}{\text{year}} \\\
In half-yearly, time is double and rate is half then we can rewrite the rate and time as,
t=32×2=3half yearly R=252×12=254%  t = \dfrac{3}{2} \times 2 = 3\,{\text{half yearly}} \\\ R = \dfrac{{25}}{2} \times \dfrac{1}{2} = \dfrac{{25}}{4}\% \\\
Now we have all the values except A which we need to calculate substitute all the value in the equation (1),\left( 1 \right),

A=4096(1+254×1100)3 =4096(1+14×14)3 =4096(1+116)3 =4096(1716)3 =4096×(49134096) =4913  A = 4096{\left( {1 + \dfrac{{25}}{4} \times \dfrac{1}{{100}}} \right)^3} \\\ = 4096{\left( {1 + \dfrac{1}{4} \times \dfrac{1}{4}} \right)^3} \\\ = 4096{\left( {1 + \dfrac{1}{{16}}} \right)^3} \\\ = 4096{\left( {\dfrac{{17}}{{16}}} \right)^3} \\\ = 4096 \times \left( {\dfrac{{4913}}{{4096}}} \right) \\\ = 4913 \\\

So by the discussion, we see that the amount isRs 4913Rs{\text{ }}4913 .
Thus, the amount is Rs 4913Rs{\text{ }}4913.

Note: Here the main point of concern is while calculating time and rate in case of half year.
We must note that if time is 11 year and rate is 1%1\% then in case of half-year time will be 22 year and the rate will be 0.5%.0.5\% .
While calculating the time year from month we must follow a unitary method of calculation.