Question

Find the amount of water displaced by a solid spherical ball of diameter.
(i) 28 cm
(ii) 0.21 m

Answer 1

(i) Radius of the ball, r = $\frac{28}{2}$ cm = 14cm
volume of the ball = $\frac{4}{3}\pi r^3$
= $\frac{4}{3} ×\frac{ 22}{7}$ $× 14$ cm $× 14$ cm $× 14$ cm

$= \frac{34496}{3}$ cm3
= 11498.66 cm3

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(ii) Radius of the ball, r =$\frac{0.21}{2}$ m = 0.105 m
volume of a ball = $\frac{4}{3}\pi r^3$
= $\frac{4}{3} ×\frac{ 22}{7}$ $× 0.105$ m $× 0.105$ m $× 0.105$ m
= 0.004851 m3