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Question

Question: Find the AM, GM and HM between the numbers 12 and 30....

Find the AM, GM and HM between the numbers 12 and 30.

Explanation

Solution

The formulas to determine arithmetic, geometric and harmonic mean between two numbers aa and bb are:
AM=a+b2, GM=(ab)12\Rightarrow AM = \dfrac{{a + b}}{2},{\text{ }}GM = {\left( {ab} \right)^{\dfrac{1}{2}}} and HM=2aba+bHM = \dfrac{{2ab}}{{a + b}}.
Use these formulas and put values of the given numbers in place of aa and bb to get the required means.

Complete step-by-step answer:
According to the question, the given two numbers are 12 and 30.
We know that the formula for finding the arithmetic mean between two numbers aa and bb is given as:
AM=a+b2\Rightarrow AM = \dfrac{{a + b}}{2}
Putting the given numbers in place of aa and bb, we’ll get:

AM=12+302 AM=422 AM=21 \Rightarrow AM = \dfrac{{12 + 30}}{2} \\\ \Rightarrow AM = \dfrac{{42}}{2} \\\ \Rightarrow AM = 21

Further, the formula for finding the geometric mean between two numbers aa and bb is given as:
GM=(ab)12=ab\Rightarrow GM = {\left( {ab} \right)^{\dfrac{1}{2}}} = \sqrt {ab}
Again putting the given numbers in place of aa and bb, we’ll get:
GM=12×30 GM=6×2×6×5 GM=610 \Rightarrow GM = \sqrt {12 \times 30} \\\ \Rightarrow GM = \sqrt {6 \times 2 \times 6 \times 5} \\\ \Rightarrow GM = 6\sqrt {10}
And the formula for finding the harmonic mean between two numbers aa and bb is given as:
HM=2aba+b\Rightarrow HM = \dfrac{{2ab}}{{a + b}}
Putting the given numbers in place of aa and bb, we’ll get:
HM=2×12×3012+30 HM=24×6×542 HM=1207 \Rightarrow HM = \dfrac{{2 \times 12 \times 30}}{{12 + 30}} \\\ \Rightarrow HM = \dfrac{{24 \times 6 \times 5}}{{42}} \\\ \Rightarrow HM = \dfrac{{120}}{7}

Thus the AM, GM and HM between the numbers 12 and 30 are 20, 61020,{\text{ 6}}\sqrt {10} and 1207\dfrac{{120}}{7} respectively.

Note: The formulas used above can be extended for more than two numbers also. If a1a2,....,an{a_1}{\text{, }}{a_2},....,{a_n} are nn different numbers, then the formula for arithmetic mean of these numbers will be:
AM=a1+a2+.....+ann\Rightarrow AM = \dfrac{{{a_1} + {a_2} + ..... + {a_n}}}{n}
Similarly, the formula for geometric mean of these numbers will be:
GM=(a1.a2....an)1n\Rightarrow GM = {\left( {{a_1}.{a_2}....{a_n}} \right)^{\dfrac{1}{n}}}
And, the formula for harmonic mean of these numbers will be:
HM=n1a1+1a2+....+1an\Rightarrow HM = \dfrac{n}{{\dfrac{1}{{{a_1}}} + \dfrac{1}{{{a_2}}} + .... + \dfrac{1}{{{a_n}}}}}