Question

Find the acceleration of $2$ $kg$ block shown in the diagram (neglect friction)

• A. $\frac{4g}{15}$
• B. $\frac{2g}{15}$
• C. $\frac{g}{15}$
• D. $\frac{2g}{3}$

Answer 1

Answer: (A)

$\frac{4g}{15}$

Answer 2

The acceleration of 2 kg block is :
The 2 kg block as shown in the diagram
$T-2g$ ; $sin$ $37 = 2a$…(i)
For the $4$ kg block
$4g-2T$
= $g-T = a$….(ii)

$2g-a-2g$ $\times \frac{3}{5}=2a$

$a = \frac{4g}{15}$

The Correct Option is (A): $\frac{4g}{15}$