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Question

Mathematics Question on geometric progression

Find the 20th and n th terms of the G.P. 52,54,58\frac{5 }{ 2} ,\frac{ 5}{ 4} ,\frac{ 5 }{ 8} ,......

Answer

The given G.P. is 52,54,58\frac{5 }{ 2} ,\frac{ 5}{ 4} ,\frac{ 5 }{ 8},......
Here, a = First term =52\frac{ 5 }{ 2} =545=12=\frac{\frac{5}{4} }{5} = \frac{1 }{ 2}
r = Common ratio = 2
a20 = ar 20-1 = 52(12)19=5(2)(2)19=5(2)20\frac{5 }{ 2} (\frac{1 }{ 2})^{19} = \frac{5 }{(2)(2)^{19}} =\frac{ 5 }{ (2)^{20}}
an = arn - 1 = 52(12)n1=5(2)(2)n1=5(2)n\frac{5 }{ 2} (\frac{1 }{ 2})^{n-1} = \frac{5 }{(2)(2)^{n-1}} =\frac{ 5 }{ (2)^{n}}