Question
Question: Find \[{\text{A}}\Delta {\text{B}}\] and by definition: \[{\text{A}} = \left\\{ {1,2,3,4,5} \right\\...
Find AΔB and by definition: {\text{A}} = \left\\{ {1,2,3,4,5} \right\\} and {\text{B}} = \left\\{ {1,3,5,7} \right\\}.
Solution
Here, we need to find the value of the expression AΔB. First, we will find the elements that come in set A but not in set B. Then, we will find the elements that come in set B but not in set A. Finally, we will use the formula for AΔB to find the elements in the set AΔB. The Δ represents the symmetric difference of two or more sets. It includes all those elements that come exactly in one set.
Formula Used:
The expression AΔB is given by the union of the elements of the set A−B, and the elements of the set B−A, that is AΔB=(A−B)∪(B−A).
Complete step-by-step answer:
The expression AΔB includes all those elements that come only in set A, or only in set B. Now, by definition, {\text{A}} = \left\\{ {1,2,3,4,5} \right\\} and {\text{B}} = \left\\{ {1,3,5,7} \right\\}.
The set A−B includes all those elements that come in set A but not in set B.
Thus, we get
{\text{A}} - {\text{B}} = \left\\{ {2,4} \right\\}
The set B−A includes all those elements that come in set B but not in set A.
Thus, we get
{\text{B}} - {\text{A}} = \left\\{ 7 \right\\}
The expression AΔB is given by the union of the elements of the set A−B, and the elements of the set B−A.
Therefore, we get
AΔB=(A−B)∪(B−A)
Substituting {\text{A}} - {\text{B}} = \left\\{ {2,4} \right\\} and {\text{B}} - {\text{A}} = \left\\{ 7 \right\\} in the expression, we get
\Rightarrow {\text{A}}\Delta {\text{B}} = \left\\{ {2,4} \right\\} \cup \left\\{ 7 \right\\}
The union of two sets is the set of all the elements in the two sets.
Thus, we get
\Rightarrow {\text{A}}\Delta {\text{B}} = \left\\{ {2,4,7} \right\\}
∴ We get AΔB as \left\\{ {2,4,7} \right\\}.
Note: The expression AΔB can be written as the difference in the union and intersection of two sets.
We can also find AΔB using the formula AΔB=(A∪B)−(A∩B).
Since {\text{A}} = \left\\{ {1,2,3,4,5} \right\\} and {\text{B}} = \left\\{ {1,3,5,7} \right\\}, we can see that
\left( {{\text{A}} \cup {\text{B}}} \right) = \left\\{ {1,2,3,4,5} \right\\} \cup \left\\{ {1,3,5,7} \right\\} = \left\\{ {1,2,3,4,5,7} \right\\}
The intersection of two sets is said to be the set of those elements which are common in both the sets.
Therefore, we get
\left( {{\text{A}} \cap {\text{B}}} \right) = \left\\{ {1,2,3,4,5} \right\\} \cap \left\\{ {1,3,5,7} \right\\} = \left\\{ {1,3,5} \right\\}
Now, substituting \left( {{\text{A}} \cup {\text{B}}} \right) = \left\\{ {1,2,3,4,5,7} \right\\} and \left( {{\text{A}} \cap {\text{B}}} \right) = \left\\{ {1,3,5} \right\\} in the formula , we get
\Rightarrow {\text{A}}\Delta {\text{B}} = \left\\{ {1,2,3,4,5,7} \right\\} - \left\\{ {1,3,5} \right\\}
Therefore, we get
\Rightarrow {\text{A}}\Delta {\text{B}} = \left\\{ {2,4,7} \right\\}
∴ We get AΔB as \left\\{ {2,4,7} \right\\}.