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Question

Mathematics Question on Trigonometric Equations

Find tan−1[(1−sin x+cos x)(1+sin x−cos x)]tan^{-1}[\frac{(1-sin\,x+cos\,x)}{(1+sin\,x-cos\,x)}] = ?

Answer

The value of tan−1(1−sin x+cos x)(1+sin x−cos x)tan^{-1}\frac{(1-sin\,x+cos\,x)}{(1+sin\,x-cos\,x)} is equal to π4\frac{\pi}{4}