Question
Question: Find real part of \({\cos h}^{- 1}(1)\)...
Find real part of cosh−1(1)
A
– 1
B
1
C
0
D
None of these
Answer
0
Explanation
Solution
We know that cosh−1x=log(x+x2−1)
∴ cosh−1(1)=log(1+12−1)= log1=0
Find real part of cosh−1(1)
– 1
1
0
None of these
0
We know that cosh−1x=log(x+x2−1)
∴ cosh−1(1)=log(1+12−1)= log1=0