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Question

Question: : Find principal and general solution of the equation \( \cot x = - \sqrt 3 \)...

: Find principal and general solution of the equation cotx=3\cot x = - \sqrt 3

Explanation

Solution

Hint : In the given problem, to find the principal solution of the given equation we will use the value of trigonometric function tanx\tan x for particular angle and also we will use basic knowledge of signs of trigonometric functions. To find a general solution of the given equation, we will use the result which is given by tanx=tanyx=nπ+y\tan x = \tan y \Rightarrow x = n\pi + y where nn is integer.

Complete step-by-step answer :
In this problem, we have to find the principal and general solution of the equation cotx=3\cot x = - \sqrt 3 . We know that tanx=1cotx\tan x = \dfrac{1}{{\cot x}} . Hence, we can write tanx=13(1)\tan x = - \dfrac{1}{{\sqrt 3 }} \cdots \cdots \left( 1 \right) .
In the equation (1)\left( 1 \right) the value of tanx\tan x is negative. Also we know that the trigonometric function tanx\tan x is negative in the second and fourth quadrant. So, we can say that xx will be in the second and fourth quadrant. Also we know that tanx=13x=π6\tan x = \dfrac{1}{{\sqrt 3 }} \Rightarrow x = \dfrac{\pi }{6} .
In the second quadrant, we can say that
x=ππ6 x=5π6   x = \pi - \dfrac{\pi }{6} \\\ \Rightarrow x = \dfrac{{5\pi }}{6} \;
In the fourth quadrant, we can say that
x=2ππ6 x=11π6   x = 2\pi - \dfrac{\pi }{6} \\\ \Rightarrow x = \dfrac{{11\pi }}{6} \;
Hence, principal solutions of the equation cotx=3\cot x = - \sqrt 3 are x=5π6x = \dfrac{{5\pi }}{6} and x=11π6x = \dfrac{{11\pi }}{6} .
Now from the equation (1)\left( 1 \right) , we can write tanx=tan5π6(2)\tan x = \tan \dfrac{{5\pi }}{6} \cdots \cdots \left( 2 \right) . We know that tanx=tanyx=nπ+y\tan x = \tan y \Rightarrow x = n\pi + y where nn is integer. Use this information in equation (2)\left( 2 \right) . So, we can write x=nπ+5π6x = n\pi + \dfrac{{5\pi }}{6} where nn is integer.
Hence, the general solution of the equation cotx=3\cot x = - \sqrt 3 is x=nπ+5π6x = n\pi + \dfrac{{5\pi }}{6} where nn is integer.

Note : The solutions of a trigonometric equation for which 0x2π0 \leqslant x \leqslant 2\pi are called principal solutions. The mathematical expression involving integer nn which gives all solutions of a trigonometric equation is called the general solution. In this type of problem, we must remember the values of trigonometric functions for particular angles. Also we must remember some trigonometric identities, results and formulas.