Question

Find out the products of the given reaction as follow:

Answer 1

In the given question, the compound which is reacting with ammonia i.e. $N{{H}_{3}}$ is an ester having chemical formula $C{{H}_{3}}COOC{{C}_{2}}{{H}_{5}}$. And, you should have knowledge that; reaction of any ester with ammonia will give its respective amide.

Complete step by step solution:
Given that,

-Before going to find out the products of the reaction, let us know what are the reactants given in the following chemical reaction.
-So, here a compound having a chemical formula $C{{H}_{3}}COOC{{C}_{2}}{{H}_{5}}$ (which is an ester) is being reacted with two molecules of ammonia (having chemical formula $N{{H}_{3}}$).
-We should know that; the following compound is a type of ester ($RO{{R}^{\prime }}$) which is formed from ethanoic acid or acetic acid (with chemical formula $C{{H}_{3}}COOH$) and propanoic acid (whose chemical formula is represented by ${{C}_{2}}{{H}_{5}}COOH$) in presence of a strong acid such as concentrated sulphuric acid, etc. On hydrolysis, the compound will dissociate to form acetic acid and propanoic acid.
-Coming to the reaction given, we should know that reaction of any ester with ammonia (i.e. $N{{H}_{3}}$) will produce its respective amide and this process is referred to as ammonolysis. So, ammonolysis is a chemical reaction which is just the same as that of a hydrolysis reaction, where ammonia reacts with another compound to form an amine. But in case of ammonolysis of organic esters, it will yield acid amides.
-So, here two molecules of ammonia acts as a nucleophile and will attack the electrophilic carbonyl carbon present in the compound (one on ethanoic acid while other on propanoic acid) and will form ethanamide ($C{{H}_{3}}CON{{H}_{2}}$) and propionamide (${{C}_{2}}{{H}_{5}}CON{{H}_{2}}$). And the balanced chemical reaction is shown as follows:

Hence, the products formed are ethanamide and propionamide.

Note: It is important to note that, ammonolysis is when ammonia acts as the nucleophile and reacts with an organic compound. The beginning of the term should help us to remember that it’s ammonia we have to deal with.