Solveeit Logo

Question

Question: Find out the mole fraction of solute in an aqueous solution of 30% NaOH....

Find out the mole fraction of solute in an aqueous solution of 30% NaOH.

Explanation

Solution

As we know that mole fraction is the way of expressing the concentration of a solution and can be described as the number of molecules or moles of a particular component in a mixture divided by the total number of moles in the given mixture. So here we have to calculate the mole fraction of solute in an aqueous solution of 30% NaOH.

Formula used:
We will use the following formula in this solution:-
xi=nintotal{{x}_{i}}=\dfrac{{{n}_{i}}}{{{n}_{\text{total}}}}
where,
xi{{x}_{i}} = mole fraction
ni{{n}_{i}} = number of moles of one component of solution
ntotal{{n}_{\text{total}}} = Total number of moles of solution

Complete answer:
Let us first begin with the calculation of mass of NaOH present in the solution followed by calculation of moles and mole fraction as follows:-
-Calculation of mass of NaOH present in an aqueous solution of 30% NaOH:-
Let us assume that the mass of the given aqueous solution is 100 grams.
So the mass of NaOH present in it = 30 grams
This means the mass of water in this solution = 70 grams.
-Calculation of number of moles of NaOH and water in the solution:-
Moles can be calculated as: n=Given massMolar mass\text{n=}\dfrac{\text{Given mass}}{\text{Molar mass}}
Molar mass of NaOH = (23 +16 + 1) g/mol = 40g/mol
Number of moles of NaOH = nNaOH=30g40g/mol=0.75moles{{\text{n}}_{NaOH}}\text{=}\dfrac{30g}{40g/mol}=0.75moles
Molar mass of H2O{{H}_{2}}O = (2 + 16) g/mol = 18g/mol
Number of moles of H2O{{H}_{2}}O= nH2O=70g18g/mol=3.89moles{{\text{n}}_{{{H}_{2}}O}}\text{=}\dfrac{70g}{18g/mol}=3.89moles
-Calculation of mole fraction of NaOH present in the solution:-
Let us substitute all the values in xi=nintotal{{x}_{i}}=\dfrac{{{n}_{i}}}{{{n}_{\text{total}}}}:-
xNaOH=nNaOHntotal xNaOH=0.75moles0.75moles+3.89moles xNaOH=0.16 \begin{aligned} & \Rightarrow {{x}_{NaOH}}=\dfrac{{{n}_{NaOH}}}{{{n}_{\text{total}}}} \\\ & \Rightarrow {{x}_{NaOH}}=\dfrac{0.75moles}{0.75moles+3.89moles} \\\ & \Rightarrow {{x}_{NaOH}}=0.16 \\\ \end{aligned}
Hence, the mole fraction of solute in an aqueous solution of 30% NaOH is 0.16.

Note:
-Remember to use the units of each given value along with it so as to easily cancel the terms with others in order to obtain an accurate answer.
-Also moles fraction is a unitless quantity.