Question
Question: Find out the mole fraction of solute in an aqueous solution of 30% NaOH....
Find out the mole fraction of solute in an aqueous solution of 30% NaOH.
Solution
As we know that mole fraction is the way of expressing the concentration of a solution and can be described as the number of molecules or moles of a particular component in a mixture divided by the total number of moles in the given mixture. So here we have to calculate the mole fraction of solute in an aqueous solution of 30% NaOH.
Formula used:
We will use the following formula in this solution:-
xi=ntotalni
where,
xi = mole fraction
ni = number of moles of one component of solution
ntotal = Total number of moles of solution
Complete answer:
Let us first begin with the calculation of mass of NaOH present in the solution followed by calculation of moles and mole fraction as follows:-
-Calculation of mass of NaOH present in an aqueous solution of 30% NaOH:-
Let us assume that the mass of the given aqueous solution is 100 grams.
So the mass of NaOH present in it = 30 grams
This means the mass of water in this solution = 70 grams.
-Calculation of number of moles of NaOH and water in the solution:-
Moles can be calculated as: n=Molar massGiven mass
Molar mass of NaOH = (23 +16 + 1) g/mol = 40g/mol
Number of moles of NaOH = nNaOH=40g/mol30g=0.75moles
Molar mass of H2O = (2 + 16) g/mol = 18g/mol
Number of moles of H2O= nH2O=18g/mol70g=3.89moles
-Calculation of mole fraction of NaOH present in the solution:-
Let us substitute all the values in xi=ntotalni:-
⇒xNaOH=ntotalnNaOH⇒xNaOH=0.75moles+3.89moles0.75moles⇒xNaOH=0.16
Hence, the mole fraction of solute in an aqueous solution of 30% NaOH is 0.16.
Note:
-Remember to use the units of each given value along with it so as to easily cancel the terms with others in order to obtain an accurate answer.
-Also moles fraction is a unitless quantity.