QuestionReportMathematics Question on Definite IntegralFind k if ∫012[x2dx(1−x2)32]=k6\int_{0}^{\frac{1}{2}}[\frac{x^2dx}{(1-x^2)^{\frac{3}{2}}}]=\frac{k}{6}∫021[(1−x2)23x2dx]=6k.AnswerThe correct answer is 23−π\sqrt{3}-\pi3−π