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Question

Mathematics Question on Integration by Parts

Find ∫−π2π2sin⁡2x1+2x  dx\int\limits^{\frac{\pi}{2}}_{-\frac{\pi}{2}} \frac{\sin^2x}{1+2^x} \;dx

A

π4\frac{\pi}{4}

B

π8\frac{\pi}{8}

C

4π

D

π2\frac{\pi}{2}

Answer

π4\frac{\pi}{4}

Explanation

Solution

The correct answer is option (A): π4\frac{\pi}{4}