Question

Find: (i) 9 $\frac{3}{2}$ (ii) 32 $\frac{2}{5}$ (iii) 16 $\frac{3}{4}$ (iv) 125 -$\frac{1}{3}$

Answer 1

(i) 9 $\frac{3}{2}$ = (9 $\frac{1}{2}$)3 $\frac{1}{3}$= (3)3 = 27

(ii) 32 $\frac{2}{5}$ = (32 $\frac{1}{5}$)2 = (2)2 = 4

(iii) 16 $\frac{3}{4}$ = (16$\frac{1}{4}$)3 = (2)3 = 8

(iv) 125 -$\frac{1}{3}$ = $\frac{1}{(125)}\frac{1}{3}$ = $\frac{1}{5}$