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Question

Economics Question on Random variables

Find dydx\frac{dy}{dx} if x1+y+y1+x=0.x\sqrt{1+y}+y\sqrt{1+x}=0.

A

−1(1+x)2\frac{-1}{(1+x)^2}

B

2(1+x)\frac{2}{(1+x)}

C

−11+x\frac{-1}{\sqrt{1+x}}

D

1+x1+y\frac{1+x}{1+y}

Answer

−1(1+x)2\frac{-1}{(1+x)^2}

Explanation

Solution

The correct answer is (A) : −1(1+x)2\frac{-1}{(1+x)^2}