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Question

Physics Question on Moving charges and magnetism

Find force per unit length at P.

A

10−4m10^{-4} m

B

10−4Nm−110^{-4} Nm^{-1}

C

3×10−4Nm−13 \times 10^{-4} Nm^{-1}

D

0.3 N/m−10.3\, N/m^{-1}

Answer

10−4Nm−110^{-4} Nm^{-1}

Explanation

Solution

Let length of wire element at P is dl. Magnetic field at B, B=μ0i4πr+0+μ0i4πrB=\frac{\mu_{0}i}{4\pi r}+0+\frac{\mu_{0}i}{4\pi r} B=μ0×54π×5×10−2×2B=\frac{\mu_{0}\times5}{4\pi\times5\times10^{-2}}\times2 B=μ04π×200B=\frac{\mu_{0}}{4\pi}\times200 B = 2 ? 10 T F = iBdl Fdi=\frac{F}{di}= iB = 5 ? 2 ? 10 = 10 N/m