Question
Question: Find equivalent resistance between A and B in the following circuit. d)
Complete answer:
The property of a material by virtue of which it resists the flow of current through it is called resistance. Its SI unit is ohms. A device which resists the flow of current in a circuit is called a resistor.
In the figure shown above, resistors are connected in series between the points A and B. The formula for equivalent resistance is given by-
R=R1+R2+−−+Rn
Substituting the value of resistors in the above equation, we get,
R′=R+2R+3R+4R+−−+100R⇒R′=(1+2+3+4+−+100)R
The above equation is a sum of terms of arithmetic progression wherein, a=1,n=100,d=1
Sum of n terms of an AP is given by the following formula-
S=2n(2a+(n−1)d)
Here, S is the sum of n terms
n is the number of terms
a is the first term of AP
d is the common difference between two consecutive terms
Given values are substituted in the above equation to get
S=2100(2×1+(100−1)×1)⇒S=50×(2+99)∴S=5050
Therefore, the sum of the following terms is 5050 and substituting the value in the equivalent resistance we get,
R′=5050R
Therefore, between points A and B, the equivalent resistance is 5050R.
Note:
Resistances can also be connected in parallel combination. The inverse of equivalent resistance of parallel combination is the sum of inverse of all resistances. The resistance is the ratio of voltage and current in a circuit by the Ohm’s law. It depends on the dimensions of a material.