Solveeit Logo

Question

Question: Find electric field at point A, B, C, D due to infinitely long uniformly charged wire with linear ch...

Find electric field at point A, B, C, D due to infinitely long uniformly charged wire with linear charge density λ and kept along z-axis (as shown in figure). Assume that all the parameters are in S.l. units.

Answer
  • Electric field at point A: EA=λ2πϵ0ri^\vec{E}_A = \frac{\lambda}{2\pi\epsilon_0 r} \hat{i}

  • Electric field at point B: EB=λ2πϵ0rj^\vec{E}_B = \frac{\lambda}{2\pi\epsilon_0 r} \hat{j}

  • Electric field at point C: EC=λ2πϵ0ri^\vec{E}_C = -\frac{\lambda}{2\pi\epsilon_0 r} \hat{i}

  • Electric field at point D: ED=λ2πϵ0rj^\vec{E}_D = -\frac{\lambda}{2\pi\epsilon_0 r} \hat{j}

Explanation

Solution

The electric field due to an infinitely long uniformly charged wire with linear charge density λ\lambda at a perpendicular distance rr from the wire is given by:

E=λ2πϵ0rE = \frac{\lambda}{2\pi\epsilon_0 r}

The direction of the electric field is radially outward from the wire if λ\lambda is positive, and radially inward if λ\lambda is negative.

Since points A, B, C, and D are located at the same perpendicular distance 'r' from the z-axis, the magnitude of the electric field at each of these points will be the same:

Emagnitude=λ2πϵ0rE_{magnitude} = \frac{\lambda}{2\pi\epsilon_0 r}

The directions at each point are as follows:

  1. Point A: Located on the positive x-axis. The electric field is directed along the positive x-axis (i^\hat{i}).

  2. Point B: Located on the positive y-axis. The electric field is directed along the positive y-axis (j^\hat{j}).

  3. Point C: Located on the negative x-axis. The electric field is directed along the negative x-axis (i^-\hat{i}).

  4. Point D: Located on the negative y-axis. The electric field is directed along the negative y-axis (j^-\hat{j}).