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Question

Physics Question on Capacitors and Capacitance

Find a capacitance
Electric circuit

A

2kAε0d\frac{2kAε_0}{d}

B

2kAε0(k+1)d\frac{2kAε_0}{(k+1)d}

C

(k+1)Aε02d\frac{(k+1)Aε_0}{2d}

D

2kAε0(k2+1)d\frac{2kAε_0}{(k^2+1)d}

Answer

2kAε0(k+1)d\frac{2kAε_0}{(k+1)d}

Explanation

Solution

The correct option is (B): 2kAε0(k+1)d\frac{2kAε_0}{(k+1)d}.