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Question: Fill in the blanks in the following conversations: i.\[1km{\text{ }} = \ldots \ldots \ldots mm{\te...

Fill in the blanks in the following conversations:
i.1km =………mm =……..pm1km{\text{ }} = \ldots \ldots \ldots mm{\text{ }} = \ldots \ldots ..pm
ii.1mg=……kg=……ng1mg = \ldots \ldots kg = \ldots \ldots ng
iii.1mL = ……L = …….1mL{\text{ }} = {\text{ }} \ldots \ldots L{\text{ }} = {\text{ }} \ldots \ldots . dm3d{m^3}

Explanation

Solution

We can do this question using unit conversions. We must keep the following things in mind and the following before a standard unit signifies certain meaning like ‘k’ signifies kilo, ‘m’ signifies milli, ‘n’ signifies nano and ‘d’ signifies deci.

Complete step by step answer:
According to standard units of measurement following the unit conversions:

(i) The relation between kilometre and millimetre is:
1km=1km = {10^3}$$$$m = {10^6}$$$$mm
The relation between picometre and metre is:
1pm=1pm = {10^{ - 12}}$$$$m and 1m=1m = {10^{12}}$$$$pm
Thus, the relation between kilometre, millimetre and picometre is as follows:
1km=1km = {10^6}$$$$mm = {10^{15}}$$$$pm

(ii) The relation between kilogram, gram and milligram is:
1kg1kg ={10^3}$$$$g = {10^6}$$$$mg
1ng=10−9g1ng = {10^{ - 9}}g , that means, 1g=  109ng1g = \;{10^9}ng
The relation between milligram, kilogram and nanogram is as follows:
1mg1mg =10−6{10^{ - 6}} kgkg ={10^6}$$$$ng

(iii) The relation between millilitre, litre and decimetre cube is as follows:
1ml1ml = 10−3{10^{ - 3}}L and 1L1L =11 dm3d{m^3}
1ml1ml = {10^{ - 3}}$$$L$ ={10^{ - 3}}$$dm3d{m^3}

Note:
A unit of measurement is defined as a unit which has a fixed value and it does not change from person to person or place to place and it is called a standard unit of measurement.
It is necessary to have standard units of measurements for the sake of uniformity in measurements. The International Standard unit of length is metre denoted by symbol (m).