Question

Fill in the blanks. (i) If $x > y$ and $z < 0$, then $-xz$ $-yz$. (ii) If $p > 0$ and $q < 0$, then $p - q$ $p$. (iii) If $-2x + 1 \ge 9$, then $x$ $-4$.

• A. a
• B. b
• C. c
• D. d

Answer 1

Answer: (D)

d

Answer 2

$(i)$ If $x > y$ and $z< 0$, then $xz< yz \quad\left[\because z<0\right]$ $\Rightarrow\quad-x z > -y z$ $\left(ii\right)$ If $p > 0$ and $q < 0$, then $p -q > p$ $\left(iii\right)$ If $-2x + 1 \ge 9$, then $-2 x \ge 9 - 1 \Rightarrow -2x\ge 8 \Rightarrow 2x\le - 8$ $\Rightarrow\quad x \le - 4\quad$ (Dividing by $2$ on both sides)