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Question: \[ \text{(Image of naphthalene)} \xrightarrow[\text{heat}]{\text{KMnO}_4, \text{H}^+} \] ...

(Image of naphthalene)→heatKMnO4,H+\text{(Image of naphthalene)} \xrightarrow[\text{heat}]{\text{KMnO}_4, \text{H}^+}
Answer

The product is the carboxylic acid derivative of tetralin, i.e. 1-(carboxymethyl)-1,2,3,4-tetrahydronaphthalene (tetralin carboxylic acid).

Explanation

Solution

Under the vigorous oxidation conditions (KMnO₄, heat, H⁺), any alkyl group attached to an aromatic ring (when a benzylic hydrogen is present) is oxidized to a carboxyl group. Here the methyl group on the benzene part of tetralin is oxidized to –COOH.