Question

T

30°

F

$\sqrt{3}$ kg

Answer 1

T = 2g, F = g

Answer 2

The system is in static equilibrium. By resolving the tension $T$ into its vertical ($T \cos 30^\circ$) and horizontal ($T \sin 30^\circ$) components, we apply Newton's first law. Vertical equilibrium ($T \cos 30^\circ = \sqrt{3}g$) gives $T = 2g$. Horizontal equilibrium ($F = T \sin 30^\circ$) then yields $F = g$.