Question

Figure shows $(x, t), (y, t)$ diagram of a particle moving in 2-dimensions. If the particle has a mass of 500 g, the force acting on the particle is

• A. 1 N along y-axis
• B. 1 N along x-axis
• C. 0.5 N along x-axis
• D. 0.5 N y-axis

Answer 1

Answer: (A)

1 N along y-axis

Answer 2

Since the graph between $x$ and $t$ is a straight line and passing through the origin. $\therefore x = t$ $\therefore y=t^{2}$ $\therefore \upsilon_{x}=\frac{dx}{dt}=1$ and $a_{x}=\frac{d\upsilon_{x}}{dt}=0$ and $\upsilon_{y}=\frac{dy}{dt}=2t$ and $a_{y}=2\,m\,s^{-2}$ The force acting on the particle is $F = ma_y = (0.5\, kg)(2\, m\, s^{-2})$ =$1 \,N$ along $y$-axis