Question

Figure shows two equipotential surfaces V₁& V₂. The component of electric field in x & y direction will be –

• A. E_x$\widehat{i}$ and E_y$\widehat{j}$
• B. – E_x$\widehat{i}$and E_y$\widehat{j}$
• C. E_x$\widehat{i}$ and – E_y$\widehat{j}$
• D. –E_x$\widehat{i}$ and – E_y$\widehat{j}$

Answer 1

Answer: (B)

– E_x$\widehat{i}$and E_y$\widehat{j}$

Answer 2

Electric field lines are perpendicular to the equipotential

surface and are directed from high potential to low potential.

\ Electric field will have one component in negative x direction and one component in + y direction.