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Question: Figure shows two capacitors C<sub>1</sub> and C<sub>2</sub> connected with 10 V battery and terminal...

Figure shows two capacitors C1 and C2 connected with 10 V battery and terminal A and B are earthed. The graph shows the variation of potential as one moves from left to right. Then the ratio of is-

A

52\frac { 5 } { 2 }

B

23\frac { 2 } { 3 }

C

25\frac { 2 } { 5 }

D

43\frac { 4 } { 3 }

Answer

23\frac { 2 } { 3 }

Explanation

Solution

= 10 – 4 = 6V

= 4 – 0 = 4V

in series =

= C1C2\frac { \mathrm { C } _ { 1 } } { \mathrm { C } _ { 2 } } = VC2 VC1\frac { \mathrm { V } _ { \mathrm { C } _ { 2 } } } { \mathrm {~V} _ { \mathrm { C } _ { 1 } } } = 46\frac { 4 } { 6 } = 23\frac { 2 } { 3 }