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Question

Physics Question on Current electricity

Figure shows three resistor configurations R1,R2R_{1}, R_{2} and R2R_{2} connected to 3V3 V battery. If the power dissipated by the configuration R1,R2R_{1}, R_{2} and R3R_{3} is P1,P2P_{1}, P_{2} and P3P_{3}, respectively, then

A

P1>P2>P3P_{1}>P_{2}>P_{3}

B

P1>P3>P2P_{1}>P_{3}>P_{2}

C

P2>P1>P3P_{2}>P_{1}>P_{3}

D

P3>P2>P1P_{3}>P_{2}>P_{1}

Answer

P2>P1>P3P_{2}>P_{1}>P_{3}

Explanation

Solution

Applying P=V2RP=\frac{V^{2}}{R},
R1=1ΩR_{1}=1 \,\Omega
R2=0.5ΩR_{2}=0.5 \,\Omega
and R3=2ΩR_{3}=2 \, \Omega
V1=V2=V3=3VV_{1}=V_{2}=V_{3}=3 V
P1=(3)21=9W\therefore P_{1}=\frac{(3)^{2}}{1}=9 \,W
P2=(3)20.5=18WP_{2}=\frac{(3)^{2}}{0.5}=18 \, W
and P3=(3)22=4.5WP_{3}=\frac{(3)^{2}}{2}=4.5 \, W
P2>P1>P3\therefore P_{2} > P_{1} > P_{3}