Question

Figure shows the displacement-time graphs of two simple harmonic motions I and II. From the graph it follows that.

• A. Curve I has same frequency as that of curve II
• B. Curve I has frequency twice that of curve II
• C. Curve I has frequency half that of curve II
• D. Curve I has frequency four times that of curve II.

Answer 1

Answer: (C)

Curve I has frequency half that of curve II

Answer 2

From the graphs

For curve I,

Time period $T_{1} = 8s,$ Frequency $\upsilon_{1} = \frac{1}{T_{1}} = \frac{1}{8}Hz$

For curve II,

Time period $T_{2} = 4s,$ Frequency $\upsilon_{2} = \frac{1}{T_{2}} = \frac{1}{4}Hz$1

Their corresponding ratio

$\frac{\upsilon_{1}}{\upsilon_{2}} = \frac{1}{2}or\upsilon_{1} = \frac{1}{2}\upsilon_{2}$