Question

Figure shows $\frac{1}{v}$ vs $\frac{1}{u}$ curve for convex mirror. Nature of image at point A is :-

• A. Real, erect, magnified
• B. virtual, inverted, magnified
• C. virtual, inverted, diminished
• D. virtual, erect, diminished

Answer 1

Answer: (D)

virtual, erect, diminished

Answer 2

The mirror formula is $\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$. For a convex mirror, the focal length $f$ is positive. The graph plots $\frac{1}{v}$ vs $\frac{1}{u}$, which can be written as $\frac{1}{v} = -\frac{1}{u} + \frac{1}{f}$.

Point A is in the first quadrant, where $\frac{1}{u} > 0$ and $\frac{1}{v} > 0$. According to the standard Cartesian sign convention:

• $u > 0$ implies the object is virtual.
• $v > 0$ implies the image is real.

However, the options do not align with this direct interpretation. Assuming the question is implicitly asking about the general nature of images formed by a convex mirror for a real object, the answer is virtual, erect, and diminished.