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Question

Physics Question on mechanical properties of solids

Figure shows a uniform rod of length 30cm30 \,cm having a mass of 3.0kg3.0 \,kg. The strings shown in the figure are pulled by constant forces of 20N20 \,N and 32N32 \,N. Find the force exerted by 20cm20 \,cm part of the rod on the 10cm10\, cm pan. All the surfaces are smooth and the strings and pulleys are light

A

36 N

B

12 N

C

64 N

D

24 N

Answer

24 N

Explanation

Solution

Net force on the rod, f=3220=12Nf=32-20=12\, N Acceleration of rod =fm=123=4ms2=\frac{f}{m}=\frac{12}{3}=4 \,ms ^{-2} Equation of motion of 10cm10\, cm part is F20=m×a=1×4F-20 =m \times a=1 \times 4 F=4+20=24NF =4+20=24\, N Similarly, Equation of motion 20cm20 \,cm part is 32F=ma=2×432-F =m' a=2 \times 4 F=328=24NF =32-8=24 \,N