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Question: Figure shows a parabolic graph between T and \(\frac{1}{V}\)for a mixture of a gas undergoing an adi...

Figure shows a parabolic graph between T and 1V\frac{1}{V}for a mixture of a gas undergoing an adiabatic process. What is the ratio of Vrms of molecules and speed of sound in mixture –

A

32\sqrt{\frac{3}{2}}

B

2\sqrt{2}

C

23\sqrt{\frac{2}{3}}

D

3\sqrt{3}

Answer

2\sqrt{2}

Explanation

Solution

T02 V0 = constant

̃ g = 3/2

VrmsVsound\frac{V_{rms}}{V_{sound}}= 3γ\sqrt{\frac{3}{\gamma}} = 2\sqrt{2}