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Question: Figure shows a man of mass 55 kg standing stationary with respect to a horizontal conveyor belt that...

Figure shows a man of mass 55 kg standing stationary with respect to a horizontal conveyor belt that is accelerating with 1 ms21 \mathrm {~ms} ^ { - 2 } . The net force acting on the man is :

A

35 N

B

45 N

C

55 N

D

65N

Answer

55 N

Explanation

Solution

Here mass of the man M=55 kgM = 55 \mathrm {~kg}

As the man is standing stationary w.rt the belt,

Acceleration of man = acceleration of belt

\thereforeAcceleration of man a=1ms2a = 1 m s ^ { - 2 }

\thereforeNet force on the man

F=Ma=(55 kg)(1 ms2)=55 NF = M a = ( 55 \mathrm {~kg} ) \left( 1 \mathrm {~ms} ^ { - 2 } \right) = 55 \mathrm {~N}