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Question

Physics Question on laws of motion

Figure shows a man of mass 55kg55\, kg standing stationary with respect to a horizontal conveyor belt that is accelerating with 1m1\,m s2s^{-2}. The net force acting on the man is

A

35N35\, N

B

45N45\, N

C

55N55\, N

D

65N65\, N

Answer

55N55\, N

Explanation

Solution

Here, mass of the man, M=55kgM=55 \,kg As the man is standing stationary w.r.t. the belt, acceleration of man = acceleration of belt. \therefore\quad Acceleration of man, a=1ma=1\, m s2s^{-2} \therefore\quad Net force on the man F=MaF=Ma =(55kg)=\left(55 \,kg\right) (1ms2)\left(1 \,m\,s^{-2}\right) =55N=55 \,N