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Question

Chemistry Question on Thermodynamics

Figure shows a copper rod joined to a steel rod. The rods have equal length and equal crosssectional area. The free end of the copper rod is kept at 0C0^{\circ} C and that of steel rod is kept at 100C100^{\circ} C. Find the temperature of the junction of the rod. Conductivity of copper =390W/mC=390 W / m ^{\circ} C. Conductivity of steel =46W/mC=46 W / m ^{\circ} C

A

18.01C18.01^\circ C

B

26C26^\circ C

C

10.6C10.6^\circ C

D

20C20^\circ C

Answer

10.6C10.6^\circ C

Explanation

Solution

Heat current in first rod (copper) =390×A(0θ)=\frac{390 \times A(0-\theta)}{\ell} Here θ\theta is temperature of the junction and A&A \& \ell are area and length of copper rod. Heat current in second rod (steel) =46×A(θ100)=\frac{46 \times A(\theta-100)}{\ell} In series combination, heat current remains same. So, 390×A(0θ)=46×A(θ100)\frac{390 \times A(0-\theta)}{\ell}=\frac{46 \times A(\theta-100)}{\ell} 390θ==46θ4600-390 \theta==46 \theta-4600 436θ=4600436 \theta=4600 4600\Rightarrow 4600 θ=10.6C\Rightarrow \theta=10.6^{\circ} C