Question
Chemistry Question on Thermodynamics
Figure shows a copper rod joined to a steel rod. The rods have equal length and equal crosssectional area. The free end of the copper rod is kept at 0∘C and that of steel rod is kept at 100∘C. Find the temperature of the junction of the rod. Conductivity of copper =390W/m∘C. Conductivity of steel =46W/m∘C
A
18.01∘C
B
26∘C
C
10.6∘C
D
20∘C
Answer
10.6∘C
Explanation
Solution
Heat current in first rod (copper) =ℓ390×A(0−θ) Here θ is temperature of the junction and A&ℓ are area and length of copper rod. Heat current in second rod (steel) =ℓ46×A(θ−100) In series combination, heat current remains same. So, ℓ390×A(0−θ)=ℓ46×A(θ−100) −390θ==46θ−4600 436θ=4600 ⇒4600 ⇒θ=10.6∘C