Question

Figure shows a circuit in which two inductors of
3 H and 6 H are connected in parallel. These are connected to a 18 volt battery with 2 W resistance. Switch S is closed at t = 0. Current as a function of time in the battery is–

• A. 9 (1 – e^–t/3) A
• B. 9 (1 – e^–t/6) A
• C. 9 (1 – e^–t/9) A
• D. None of these

Answer 1

Answer: (D)

None of these

Answer 2

L = 2H

R = 2W

E = 18 V

I = $\frac { E } { R }$ $\left( 1 - e^{- \frac{R}{L}t} \right)$

I = 9 (1 – e^–t)