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Question

Question: Figure shows a capillary tube of radius r dipped into water. If the atmospheric pressure is $P_0$, t...

Figure shows a capillary tube of radius r dipped into water. If the atmospheric pressure is P0P_0, the pressure at point A is

A

P0P_0

B

P0+2SrP_0 + \frac{2S}{r}

C

P02SrP_0 - \frac{2S}{r}

D

P04SrP_0 - \frac{4S}{r}

Answer

$P_0 - \frac{2S}{r}

Explanation

Solution

Using Laplace’s equation, the pressure difference across a curved surface is

ΔP=2Sr\Delta P = \frac{2S}{r}

Since the meniscus is concave, the pressure inside the liquid at point A is less than the atmospheric pressure by this amount. Thus,

PA=P02SrP_A = P_0 - \frac{2S}{r}