Question

$\longrightarrow$ HO-X + H$^+$ $\longrightarrow$

Answer 1

The reaction shown is the formation of a halohydrin from propene and HO-X. The product is 1-halo-2-propanol.

Answer 2

The reaction is an electrophilic addition of HO-X to propene. The addition follows Markovnikov's rule, where the hydroxyl group (-OH) adds to the more substituted carbon of the double bond, and the halogen atom (-X) adds to the less substituted carbon. This leads to the formation of a halohydrin.