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Question: ```latex \begin{array}{lll} \square & \text{Q is} & \includegraphics[width=2cm]{im1.png} \\ \square...

\begin{array}{lll}
\square & \text{Q is} & \includegraphics[width=2cm]{im1.png} \\
\square & \text{S is} & \includegraphics[width=2cm]{im2.png} \\
\square & \text{Q is} & \includegraphics[width=2cm]{im3.png} \\
\square & \text{R is} & \includegraphics[width=2cm]{im4.png}
\end{array}
A

Q is includegraphics[width=2cm]{im1.png}

B

S is includegraphics[width=2cm]{im2.png}

C

Q is includegraphics[width=2cm]{im3.png}

D

R is includegraphics[width=2cm]{im4.png}

Answer

S is includegraphics[width=2cm]{im2.png}

Explanation

Solution

The reaction sequence starts with catechol reacting with NaOH to form the monosodium salt P.

P reacts with chloroacetyl chloride to form Q, which is 2-(2-hydroxyphenoxy)acetyl chloride.

Q reacts with NaOH to form R, which is 2,3-dihydro-1,4-benzodioxin-2-one via intramolecular cyclization.

R is reduced by LiAlH4 to form S, which is 2-(2-hydroxyphenoxy)ethanol.

Therefore, the statement "S is 2-(2-hydroxyphenoxy)ethanol" is correct.