Question

The output of the given circuit diagram is

• A. \begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 0 \\\ 1 & 0 & 0 \\\ 0 & 1 & 0 \\\ 1 & 1 & 1 \\\ \hline \end{array}
• B. \begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 0 \\\ 1 & 0 & 1 \\\ 0 & 1 & 1 \\\ 1 & 1 & 0 \\\ \hline \end{array}
• C. \begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 0 \\\ 1 & 0 & 1 \\\ 0 & 1 & 0 \\\ 1 & 1 & 0 \\\ \hline \end{array}
• D. \begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 0 \\\ 1 & 0 & 0 \\\ 0 & 1 & 1 \\\ 1 & 1 & 0 \\\ \hline \end{array}

Answer 1

Answer: (C)

\begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 0 \\\ 1 & 0 & 1 \\\ 0 & 1 & 0 \\\ 1 & 1 & 0 \\\ \hline \end{array}

Answer 2

The circuit diagram consists of logic gates. By analyzing each gate’s behavior step-by-step and evaluating the output $Y$ for each input combination of $A$ and $B$, we can determine the output for each case. After constructing the truth table for the circuit, we find that the correct output matches option (3).

Thus, the answer is:

\begin{array}{|c|c|c|} \hline A & B & Y \\\ \hline 0 & 0 & 1 \\\ 1 & 1 & 0 \\\ 1 & 0 & 0 \\\ 0 & 1 & 1 \\\ \hline \end{array}