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Question: Find out the major product for the above reaction. [Main July 28, 2022] ...

Find out the major product for the above reaction. [Main July 28, 2022]

A

(a)

B

(b)

C

(c)

D

(d)

Answer

a

Explanation

Solution

The reaction proceeds via iodolactonization, forming a 5-membered iodo-lactone (γ-lactone) as the major intermediate due to favored 5-membered ring formation. The carboxylate oxygen attacks C1 of the double bond, placing iodine on C2. Subsequent dehydroiodination (elimination of HI) by pyridine and heat leads to the formation of a double bond between C1 and C2, resulting in an α,β-unsaturated lactone. This product matches option (a).