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Question: A thick spherical shell of inner and outer radii r and R respectively has thermal conductivity $k = ...

A thick spherical shell of inner and outer radii r and R respectively has thermal conductivity k=ρxnk = \frac{\rho}{x^n}, where ρ\rho is a constant and x is distance from the center of the shell. The inner and outer walls are maintained at temperature T1T_1 and T2(<T1)T_2 (< T_1). The value of number n (call it n0n_0) for which the temperature gradient remains constant throughout the thickness of the shell will be:-

A

1

B

2

C

3

D

4

Answer

2

Explanation

Solution

For steady-state heat conduction in a spherical shell, the rate of heat flow HH is given by H=k(4πx2)dTdxH = -k(4\pi x^2) \frac{dT}{dx}. Substituting the given thermal conductivity k=ρxnk = \frac{\rho}{x^n}, we get H=ρxn(4πx2)dTdxH = - \frac{\rho}{x^n} (4\pi x^2) \frac{dT}{dx}. Rearranging for the temperature gradient, dTdx=H4πρxn2\frac{dT}{dx} = -\frac{H}{4\pi\rho} x^{n-2}. For the temperature gradient to be constant, the exponent of xx must be zero. Thus, n2=0n-2 = 0, which gives n=2n=2.