Question

A 1 $\Omega$ C 3 $\Omega$ B 5 $\Omega$

Answer 1

B 5 \Omega

Answer 2

The circuit consists of three resistors forming a triangle. To find the equivalent resistance between points A and B, identify the parallel paths. The direct path between A and B has a 5 $\Omega$ resistor. The other path goes from A to C (1 $\Omega$) and then from C to B (3 $\Omega$). These two resistors (1 $\Omega$ and 3 $\Omega$) are in series, giving a total of 4 $\Omega$ for this path. Now, the 5 $\Omega$ resistor (direct path) and the 4 $\Omega$ series combination (path through C) are in parallel. The equivalent resistance is calculated as $\frac{5 \times 4}{5 + 4} = \frac{20}{9} \, \Omega$. Since this value is not among the options, and the option format is unusual, it's possible the question implicitly asks for the resistance of the direct branch between A and B, which is 5 $\Omega$.