Question

The provided image shows a chemical structure: Benzyl phenyl ketone (Ph-CO-CH2-Ph) followed by a reaction arrow. The question itself is not explicitly stated, making it incomplete. However, to provide a solution as required, we will assume a common and fundamental reaction for ketones in the context of JEE and NEET preparation. A very common reaction for ketones is reduction. We will assume the question asks for the product of reduction using a mild reducing agent like Sodium Borohydride (NaBH4).

• A. 1,2-diphenylethanol
• B. 1,1-diphenylethanol
• C. Benzyl phenyl ether
• D. Diphenylmethane

Answer 1

Answer: (A)

1,2-diphenylethanol

Answer 2

Benzyl phenyl ketone has the structure $\text{C}_6\text{H}_5\text{-CO-CH}_2\text{-C}_6\text{H}_5$. Sodium borohydride (NaBH4) is a mild reducing agent that reduces ketones to secondary alcohols. The carbonyl group (C=O) is converted to a hydroxyl group (CH-OH). Therefore, the product of the reaction is $\text{C}_6\text{H}_5\text{-CH(OH)-CH}_2\text{-C}_6\text{H}_5$, which is 1,2-diphenylethanol.