Question

The problem asks to find the equivalent resistance of the given circuit. The circuit shows three resistors connected in a delta (triangle) configuration, with resistances 2 Ω, 3 Ω, and 5 Ω between points A-C, C-B, and A-B respectively. Since the question does not specify between which two points the equivalent resistance is to be calculated, we will calculate it between points A and B, which is a common convention for such problems.

Answer 1

The equivalent resistance between points A and B is 2.5 Ω.

Answer 2

The circuit forms a delta (triangle) configuration. To find the equivalent resistance between two terminals (say, A and B), the resistor directly connecting these terminals (5 Ω) is in parallel with the series combination of the other two resistors (2 Ω and 3 Ω). The series combination is 2+3=5 Ω. The parallel combination of 5 Ω and 5 Ω yields $R_{eq} = \frac{5 \times 5}{5+5} = \frac{25}{10} = 2.5 \, \Omega$.