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Question

Question: The problem presents a complex circuit diagram with multiple voltage sources and resistors, along wi...

The problem presents a complex circuit diagram with multiple voltage sources and resistors, along with nine numbered nodes. The goal is to determine the potential at each of these numbered nodes.

Answer

V1=2V, V2=8V, V3=8V, V4=5V, V5=9V, V6=8V, V7=8V, V8=0V, V9=8V

Explanation

Solution

The solution uses Nodal Analysis to determine the potential at each node in the circuit. Here's a breakdown of the steps:

  1. Choose a Reference Node: Node 8 is chosen as the reference node (ground) and assigned a potential of 0V, i.e., V8=0VV_8 = 0V.

  2. Determine Potentials of Directly Connected Nodes:

    • Node 6: Since an 8V voltage source is connected between Node 8 (negative terminal) and Node 6 (positive terminal), V6=8VV_6 = 8V.
  3. Interpret the Central Connections: The diagram shows direct wire connections from the central Node 9 to Nodes 2, 3, 6, and 7. This implies that all these nodes are at the same electrical potential. Therefore: V9=V2=V3=V6=V7=8VV_9 = V_2 = V_3 = V_6 = V_7 = 8V.

  4. Determine Remaining Node Potentials using Voltage Sources:

    • Node 4: A 3V voltage source is connected between Node 4 (negative terminal) and Node 2 (positive terminal). Thus, V4=V23V=8V3V=5VV_4 = V_2 - 3V = 8V - 3V = 5V.
    • Node 1: A 6V voltage source is connected between Node 1 (negative terminal) and Node 3 (positive terminal). Thus, V1=V36V=8V6V=2VV_1 = V_3 - 6V = 8V - 6V = 2V.
    • Node 5: A 1V voltage source is connected between Node 7 (negative terminal) and Node 5 (positive terminal). Thus, V5=V7+1V=8V+1V=9VV_5 = V_7 + 1V = 8V + 1V = 9V.
  5. Summary of Node Potentials:

    • V1=2VV_1 = 2V
    • V2=8VV_2 = 8V
    • V3=8VV_3 = 8V
    • V4=5VV_4 = 5V
    • V5=9VV_5 = 9V
    • V6=8VV_6 = 8V
    • V7=8VV_7 = 8V
    • V8=0VV_8 = 0V
    • V9=8VV_9 = 8V

The key is to use Nodal Analysis, choosing a reference node, and then using the voltage sources and direct wire connections to determine the potentials at all other nodes.