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Question: A cyclopropyl ether ketone is treated with $\text{H}_2\text{O}^{18}$ in the presence of acid. Which...

A cyclopropyl ether ketone is treated with H2O18\text{H}_2\text{O}^{18} in the presence of acid. Which of the following is the major product?

(Image of a cyclopropyl ether ketone reacting with H2O18\text{H}_2\text{O}^{18} and acid to form several possible products labeled A, B, C, and D.)

A

Product A

B

Product B

C

Product C

D

Product D

Answer

Product A

Explanation

Solution

The reaction involves the acid-catalyzed hydrolysis of a cyclopropyl ether ketone with heavy water (H2O18\text{H}_2\text{O}^{18}). The strained cyclopropane ring and the ether linkage are cleaved. Protonation of the ether oxygen activates the ring for nucleophilic attack by water. The mechanism involves ring opening, likely forming a carbocation intermediate, followed by attack by H2O18\text{H}_2\text{O}^{18}. Rearrangements occur, leading to the incorporation of O18\text{O}^{18} into the molecule, specifically at the aldehyde group in Product A, which is a γ\gamma-ketoaldehyde.