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Question: Few electrons have following quantum numbers, (i) n = 4, l = 1 (ii) n = 4, l =0 (iii) n = 3, l = 2...

Few electrons have following quantum numbers,

(i) n = 4, l = 1 (ii) n = 4, l =0

(iii) n = 3, l = 2 (iv) n = 3, l – 1

Arrange them in the order of increasing enrgy from lowest to highest.

A

(iv) < (ii)<(iii) <(i)

B

(ii)<(iv)<(i)<(iii)

C

(i)< (iii)< (ii)< (iv)

D

(iii)<(i)< (iv)<(ii)

Answer

(iv) < (ii)<(iii) <(i)

Explanation

Solution

: (i) 4p, (ii) 4s, (iii) 3d, (iv) 3p

The order of increasing energy,

(iv)< (ii)< (iii)< (i)