Question
Chemistry Question on Law Of Chemical Equilibrium And Equilibrium Constant
FeO42−+2.2vFe3++0.70vFe2+−0.45vFe0
EFeO42+0isx×10−3V. The Value of x is __
Answer
The Answer is 1825
FeO42−+2.2vFe3++0.70vFe2+−0.45vFe0
EFeO42+0isx×10−3V. The Value of x is __
The Answer is 1825