Question
Chemistry Question on d -and f -Block Elements
[Fe(H2O)6]2[Fe(CN)6] Cationic and anionic species spin only magnetic moment in Bohr magneton is :
A
4.89 and 0
B
5.9 and 0
C
0 and 4.89
D
2.82 and 2.82
Answer
4.89 and 0
Explanation
Solution
{[Fe^{+2} (H2O)6]^{2+}} \hspace35mm {[Fe^{+2} (CN)6]^{4-} } { Fe^{2+} \Rightarrow [Ar] 3d^6 } \hspace35mm { Fe^{2+} \Rightarrow [Ar] 3d^6 } { H_2 O \Rightarrow WFL } \hspace40mm {CN^{-} \Rightarrow SFL} Number of unpaired electrons = 4 \hspace4mm Number of unpaired electrons = 0 \mu = \sqrt{ n(n +2)} = 4.89 BM \hspace15mm \mu = 0